走进 Rust:迭代器

Rust About 1,040 words

遍历求和

iter()获取迭代器,sum()求和。

#[test]
fn iterator_sum() {
    let v1 = vec![1, 2, 3];

    let v1_iter = v1.iter();

    let total: i32 = v1_iter.sum();

    assert_eq!(total, 6);
}

map

集合中的元素每个都加1

let v1: Vec<i32> = vec![1, 2, 3];

let v2: Vec<_> = v1.iter().map(|x| x + 1).collect();

assert_eq!(v2, vec![2, 3, 4]);

自定义迭代器

实现Iteratortrait

struct Counter {
    count: u32,
}

impl Counter {
    fn new() -> Counter {
        Counter { count: 0 }
    }
}

impl Iterator for Counter {
    type Item = u32;

    fn next(&mut self) -> Option<Self::Item> {
        self.count += 1;

        if self.count < 6 {
            Some(self.count)
        } else {
            None
        }
    }
}

#[test]
fn calling_next_directly() {
    let mut counter = Counter::new();

    assert_eq!(counter.next(), Some(1));
    assert_eq!(counter.next(), Some(2));
    assert_eq!(counter.next(), Some(3));
    assert_eq!(counter.next(), Some(4));
    assert_eq!(counter.next(), Some(5));
    assert_eq!(counter.next(), None);
}
Views: 2,415 · Posted: 2020-08-06

————        END        ————

Give me a Star, Thanks:)

https://github.com/fendoudebb/LiteNote

扫描下方二维码关注公众号和小程序↓↓↓

扫描下方二维码关注公众号和小程序↓↓↓


Today On History
Browsing Refresh