走进 Rust:迭代器
Rust About 1,040 words遍历求和
iter()
获取迭代器,sum()
求和。
#[test]
fn iterator_sum() {
let v1 = vec![1, 2, 3];
let v1_iter = v1.iter();
let total: i32 = v1_iter.sum();
assert_eq!(total, 6);
}
map
集合中的元素每个都加1
。
let v1: Vec<i32> = vec![1, 2, 3];
let v2: Vec<_> = v1.iter().map(|x| x + 1).collect();
assert_eq!(v2, vec![2, 3, 4]);
自定义迭代器
实现Iterator
的trait
。
struct Counter {
count: u32,
}
impl Counter {
fn new() -> Counter {
Counter { count: 0 }
}
}
impl Iterator for Counter {
type Item = u32;
fn next(&mut self) -> Option<Self::Item> {
self.count += 1;
if self.count < 6 {
Some(self.count)
} else {
None
}
}
}
#[test]
fn calling_next_directly() {
let mut counter = Counter::new();
assert_eq!(counter.next(), Some(1));
assert_eq!(counter.next(), Some(2));
assert_eq!(counter.next(), Some(3));
assert_eq!(counter.next(), Some(4));
assert_eq!(counter.next(), Some(5));
assert_eq!(counter.next(), None);
}
Views: 2,485 · Posted: 2020-08-06
————        END        ————
Give me a Star, Thanks:)
https://github.com/fendoudebb/LiteNote扫描下方二维码关注公众号和小程序↓↓↓
Loading...