数据结构:双向链表

数据结构 About 3,071 words

定义双向节点

type DoublyNode struct {
    No   int
    Name string
    Pre  *DoublyNode
    Next *DoublyNode
}

定义双向链表

type DoublyLinkedList struct {
    HeadNode *DoublyNode
}

从尾部添加

指针移动到链表尾部即可。

func (list *DoublyLinkedList) Add(no int, name string) {
    node := &DoublyNode{
        No:   no,
        Name: name,
    }
    temp := list.HeadNode
    if temp == nil {
        list.HeadNode = node
        return
    }

    for temp.Next != nil {
        temp = temp.Next
    }

    temp.Next = node
    node.Pre = temp
}

删除指定编号的节点

遍历到当前节点的编号等于传入的参数即可。

func (list *DoublyLinkedList) Delete(no int) {
    temp := list.HeadNode
    for temp != nil {
        if temp.No == no {
            temp.Pre.Next = temp.Next
            temp.Next.Pre = temp.Pre
            temp.Next = nil
            temp.Pre = nil
            break
        }
        temp = temp.Next
    }
}

按顺序插入节点 方式一

遍历到当前节点的编号大于插入节点的编号即可,但要注意,若是插入到链表末尾则需手动break跳出循环。

func (list *DoublyLinkedList) Insert(no int, name string) {
    node := &DoublyNode{
        No:   no,
        Name: name,
    }

    if list.HeadNode == nil {
        list.HeadNode = node
        return
    }

    temp := list.HeadNode

    for temp != nil {
        if temp.No > node.No {
            if temp.Pre == nil {
                // 此时temp为头节点
                node.Next = temp
                temp.Pre = node
                list.HeadNode = node
            } else {
                node.Next = temp
                node.Pre = temp.Pre
                temp.Pre.Next = node
                temp.Pre = node
            }
            break
        } else {
            if temp.Next == nil {
                // 到了链表末尾,此时插入的节点 No 数值最大
                node.Pre = temp
                temp.Next = node
                // 末尾新增了一个节点,必须break,否则将无限循环
                break
            }
        }
        temp = temp.Next
    }
}

按顺序插入节点 方式二

遍历当前节点,并判断当前节点的下一个节点是否大于插入节点的编号即可。

func (list *DoublyLinkedList) Insert2(no int, name string) {
    node := &DoublyNode{
        No:   no,
        Name: name,
    }

    if list.HeadNode == nil {
        list.HeadNode = node
        return
    }

    temp := list.HeadNode
    if temp.No > node.No {
        node.Next = temp
        temp.Pre = node
        list.HeadNode = node
    } else {
        for temp.Next != nil {
            if temp.Next.No > no {
                break
            }
            temp = temp.Next
        }

        node.Next = temp.Next
        node.Pre = temp
        if temp.Next != nil {
            temp.Next.Pre = node
        }
        temp.Next = node
    }
}

测试代码

func main() {
    doublyLinkedList := &DoublyLinkedList{}
    doublyLinkedList.Insert2(3, "333")
    doublyLinkedList.Insert2(1, "111")
    doublyLinkedList.Insert2(2, "222")
    doublyLinkedList.Delete(2)
    doublyLinkedList.Add(4, "444")
    doublyLinkedList.Add(5, "555")

    doublyLinkedList.Print()
}

func (list *DoublyLinkedList) Print() {
    temp := list.HeadNode
    for temp != nil {
        fmt.Println("No#", temp.No, "Name#", temp.Name)
        temp = temp.Next
    }
}
Views: 1,313 · Posted: 2021-01-20

————        END        ————

Give me a Star, Thanks:)

https://github.com/fendoudebb/LiteNote

扫描下方二维码关注公众号和小程序↓↓↓

扫描下方二维码关注公众号和小程序↓↓↓


Today On History
Browsing Refresh