SQL 查询出成绩表中成绩大于 90 的学生名字
SQL 面试 About 1,004 words成绩表
mysql> select * from test_score;
+----+---------+---------+-------+
| id | student | subject | score |
+----+---------+---------+-------+
| 1 | 张三 | 语文 | 95 |
| 2 | 张三 | 数学 | 95 |
| 3 | 张三 | 英语 | 95 |
| 4 | 李四 | 语文 | 95 |
| 5 | 李四 | 数学 | 85 |
| 6 | 李四 | 英语 | 95 |
| 7 | 王五 | 语文 | 85 |
| 8 | 王五 | 数学 | 80 |
| 9 | 王五 | 英语 | 95 |
+----+---------+---------+-------+
问题一
查找出每门课成绩都大于等于90
的学生名字
select * from test_score group by student HAVING MIN(score) >= 90
输出:
mysql> select student from test_score group by student HAVING MIN(score) >= 90;
+---------+
| student |
+---------+
| 张三 |
+---------+
问题二
两门或两门以上的课成绩大于等于90
select student from test_score where score >= 90 group by student HAVING count(student) >= 2
输出:
mysql> select student from test_score where score >= 90 group by student HAVING count(student) >= 2;
+---------+
| student |
+---------+
| 张三 |
| 李四 |
+---------+
Views: 4,231 · Posted: 2022-04-12
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